Step 1 Add the inches. Step 2 Add the feet. \[ \begin{array}{rr} 2 \mathrm{ft} & 9 \mathrm{in} \\ +1 \mathrm{ft} & 7 \mathrm{in} \\ \hline 16 \mathrm{in} \end{array} \] Step 3 If the inches total more than 12 , use a proportion to change the remainder into feet and inches. \[ \begin{array}{r} 2 \mathrm{ft} \quad 9 \mathrm{in} \\ +1 \mathrm{ft} \quad 7 \mathrm{in} \\ \hline 3 \mathrm{ft} \quad 16 \mathrm{in} \end{array} \] Step 4 Add to get the final answer. \[ \begin{aligned} \frac{1 \mathrm{ft}}{12 \mathrm{in}} & =\frac{n}{16 \mathrm{in}} \\ 12 n & =16 \\ n & =1 \mathrm{ft} 4 \mathrm{in} \end{aligned} \] Study these examples. Add. Change the remainders into feet and inches. (1) \[ \begin{array}{r} 2 \mathrm{H} \quad 7 \mathrm{in} \\ +4 \mathrm{H} \quad 8 \mathrm{in} \\ \hline 6415 \mathrm{in} \end{array} \] (2) \[ \begin{array}{r} 3 \mathrm{ft} \quad 6 \mathrm{in} \\ +4 \mathrm{ft} \quad 10 \mathrm{in} \\ \hline 7 \mathrm{ft} 16 \mathrm{in} \end{array} \] (3) \[ \begin{array}{r} 5 \mathrm{ft} \quad 10 \mathrm{in} \\ +5 \mathrm{ft} \quad 10 \mathrm{in} \\ \hline 10 \mathrm{ft} 20 \mathrm{in} \end{array} \] (4) \[ \begin{array}{r} 5 \mathrm{ft} 8 \mathrm{in} \\ +1 \mathrm{ft} 9 \mathrm{in} \\ \hline 6 \mathrm{ft} 12 \mathrm{im} \end{array} \] 6
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- \(9 \, \text{in} + 7 \, \text{in} = 16 \, \text{in}\) Show more…
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Add or subtract as indicated. (See Example 3.) $2 \mathrm{ft} 8 \mathrm{in.}+3 \mathrm{ft} 4 \mathrm{in.}$
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