Question

Step 4 There are four suits in the deck: \( \square \) \( \times \) spades \( \square \) \( x \) diamonds \( \square \) \( x \) hearts, and \( \square \) \( \times \) clubs .There is an equal number of cards of each suit. Since there are 1,716 hands consisting of entirely \( \square \) , we can deduce that there are another 1,716 hands consisting entirely of \( \square \) \( x \) diamonds , another 1,716 consisting entirely of \( \square \) \( x \) hearts , and another 1,716 consisting entirely of \( x \) clubs. In other words, there is a total of \( 4(1,716)= \) \( \square \) hands consisting of entirely one suit. We previously determined that there are 20,358,520 total possible hands. Substitute the appropriate values to calculate the desired probability, rounding the result to six decimal places. \[ \begin{aligned} P(\text { hand consists entirely of one suit) } & =\frac{\text { number of hands consisting of entirely one suit }}{\text { number of total possible hands }} \\ & =\square \\ & =\square \end{aligned} \] SUBMIT SKIP (YOU CANNOT COME BACK)

          Step 4

There are four suits in the deck: \( \square \) \( \times \) spades \( \square \) \( x \) diamonds \( \square \) \( x \) hearts, and \( \square \) \( \times \) clubs .There is an equal number of cards of each suit. Since there are 1,716 hands consisting of entirely
\( \square \) , we can deduce that there are another 1,716 hands consisting entirely of \( \square \) \( x \) diamonds , another 1,716 consisting entirely of \( \square \) \( x \) hearts , and another 1,716 consisting entirely of \( x \) clubs. In other words, there is a total of \( 4(1,716)= \) \( \square \) hands consisting of entirely one suit.

We previously determined that there are 20,358,520 total possible hands.
Substitute the appropriate values to calculate the desired probability, rounding the result to six decimal places.
\[
\begin{aligned}
P(\text { hand consists entirely of one suit) } & =\frac{\text { number of hands consisting of entirely one suit }}{\text { number of total possible hands }} \\
& =\square \\
& =\square
\end{aligned}
\]
SUBMIT
SKIP (YOU CANNOT COME BACK)

Step 4

There are four suits in the deck: □ × spades □ x diamonds □ x hearts, and □ × clubs .There is an equal number of cards of each suit. Since there are 1,716 hands consisting of entirely
□ , we can deduce that there are another 1,716 hands consisting entirely of □ x diamonds , another 1,716 consisting entirely of □ x hearts , and another 1,716 consisting entirely of x clubs. In other words, there is a total of 4(1,716)= □ hands consisting of entirely one suit.

We previously determined that there are 20,358,520 total possible hands.
Substitute the appropriate values to calculate the desired probability, rounding the result to six decimal places.

P( hand consists entirely of one suit) =( number of hands consisting of entirely one suit )/( number of total possible hands )
=□
=□

SUBMIT
SKIP (YOU CANNOT COME BACK)

Added by Karen F.

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