00:01
So in this question we have these two circuits.
00:04
So in the first case, as you can see, all the bulbs are in series.
00:10
All the bulbs are in series.
00:17
So same amount of current flows through each of the, through each bulb.
00:38
That's why there will be all the brightness of the all the bulbs will be same.
00:45
So brightness will be same for all the bulbs.
00:47
Same amount of parent is flowing, see brightness is same for all the body.
01:02
This is for the first case, okay, the circuit for the first one, this one.
01:07
Now in the second case we are adding another bulb in parallel with b and it is having a resistance greater than the resistances of a b and c.
01:18
Actually in this case what is happening actually? so as we are adding the bulb in parallel, that it is a resistance greater than the resistance of a, b and c.
01:25
Equivalent resistance of the circuit is decreased from the previous case because we know that in case of parallel combination in case of parallel combination equivalent resistance resistance is less than the least resistance in the combination okay so as you can see if let's say the resistances are r r in the first case so in the first case, the equivalent resistance was 3r, r plus r plus r.
02:33
Now the equivalent resistance is r plus r for a and c, and for parallel combination bd, now the equivalent resistance rp is less than r because now this rp is less than r.
02:52
So actually the equivalent resistance will be less.
02:57
That means the current will be higher to a.
03:00
So, a will be brighter.
03:04
So in the next, for the second case, a will be brighter.
03:14
Okay, as the current is greater now.
03:18
Okay, thank you.
03:22
Now in the next part, you can see that as in the second circuit, the total current has increased.
03:31
So that means now the potential drop across a and c is greater than the previous case...