Question

Study the following Java code: Node n1 = new Node(2); int i; for (i=1; i<=5; i++) n1 = new Node(2*i, n1); n1.getNext().getNext().setData(i); for (i=1; i<=2; i++) n1 = n1.getNext(); When the above code executes the result is a sequence of linked nodes. The number of nodes in the sequence is . The value in the first node is and the value in the last node is .

Name: study the following java code node n1 new node2 int i for i1 i5 i n1 new node2i n1 n1getnextgetnextsetdatai for i1 i2 i n1 n1getnext when the above code executes the result is a sequence of 90962
Uploaded: 2023-07-24T08:22:37-08:00
Duration: 2 min 28 s
Channel: Adi S
Description: study the following java code node n1 new node2 int i for i1 i5 i n1 new node2i n1 n1getnextgetnextsetdatai for i1 i2 i n1 n1getnext when the above code executes the result is a sequence of 90962

          Study the following Java code:
Node n1 = new Node(2);
int i;
for (i=1; i<=5; i++)
    n1 = new Node(2*i, n1);
n1.getNext().getNext().setData(i);
for (i=1; i<=2; i++)
    n1 = n1.getNext();
When the above code executes the result is a sequence of linked nodes. The number of nodes in the sequence is
. The value in the first node is
and the value in the last node is
.

Added by Diana S.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Adi S

07/24/2023

Step 1

This means the first node in the linked list has a value of `2`. Show more…

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Study the following Java code: Node n1 = new Node(2); int i; for (i=1; i<=5; i++) n1 = new Node(2*i, n1); n1.getNext().getNext().setData(i); for (i=1; i<=2; i++) n1 = n1.getNext(); When the above code executes the result is a sequence of linked nodes. The number of nodes in the sequence is . The value in the first node is and the value in the last node is .