00:01
So in this question, the signal of x of t is given by cost 200 pi t.
00:10
So the operating frequency of the signal that is w is equal to 200 pi 2 pi and so this from this frequency will be equal to 200 pi f which is equal to 1 k now the time period will be t is equal to basically 1 upon f so this means time period will be 1 in second so the graph plotting will be like this xx and y xx is so basically in yxas we have x of 1 by v and in xxas we have t so let's label it so this is basically 0 .001.
01:01
0 .002, 0 .003 and 0 .004.
01:09
So basically the graph starts from like this, moving like this.
01:17
So this move graph move like this.
01:24
So this is basically the graph between x of 1 by v and t.
01:30
Now for the sampling frequency, sampling frequency, f of s is equal to 2k h z basically sampling time will be equal to this is about the sampling time this is given by t of s will be equal to 1 upon f of s which is equal to 1 upon 2 k which is equal to 0 .5 m second and this can also be written as 0 .000000 so let's plot a table.
02:14
So this is basically about t and here we have in second column we have cost 200 by t.
02:25
This is column.
02:27
So this here we have 0.
02:28
So this value will be 1.
02:30
If we have 0 .005, the value will be minus 1.
02:33
If we have value of 0 .0010, so the value will be 1.
02:39
If we have 0 .0015, so the value of cost 200 pi, t, will be of minus 1...