Question

SUBMIT ANSWER 15. [-/3 Points] DETAILS MY NOTES LARPCALCLIM4HS 10.3.033. ASK YOUR TEACHER PRACTICE ANOTHER Find the center, vertices, foci, and eccentricity of the ellipse. $4x^2 + y^2 = 64$ center (x, y) = vertices (x, y) = ) (smaller y-value) (x, y) = (larger y-value)

Name: submit answer 15 3 points details my notes larpcalclim4hs 103033 ask your teacher practice another find the center vertices foci and eccentricity of the ellipse 4x2 y2 64 center x y vertices 93962
Uploaded: 2022-01-13T00:15:29-08:00
Duration: 3 min 35 s
Channel: James Kiss
Description: submit answer 15 3 points details my notes larpcalclim4hs 103033 ask your teacher practice another find the center vertices foci and eccentricity of the ellipse 4x2 y2 64 center x y vertices 93962

          SUBMIT ANSWER
15. [-/3 Points] DETAILS
MY NOTES LARPCALCLIM4HS 10.3.033.
ASK YOUR TEACHER
PRACTICE ANOTHER
Find the center, vertices, foci, and eccentricity of the ellipse.
$4x^2 + y^2 = 64$
center
(x, y) =
vertices
(x, y) =
) (smaller y-value)
(x, y) =
(larger y-value)

submit answer 15 3 points details my notes larpcalclim4hs 103033 ask your teacher practice another find the center vertices foci and eccentricity of the ellipse 4x2 y2 64 center x y vertices 93962

Added by Brandy H.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert James Kiss

01/13/2022

Step 1

To find the standard form of the ellipse equation, we need to divide both sides by 64: $\frac{4x^2}{64} + \frac{y^2}{64} = \frac{64}{64}$ $\frac{x^2}{16} + \frac{y^2}{64} = 1$ Step 2: The standard form of an ellipse centered at (h, k) is $\frac{(x-h)^2}{a^2} + Show more…

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SUBMIT ANSWER 15. [-/3 Points] DETAILS MY NOTES LARPCALCLIM4HS 10.3.033. ASK YOUR TEACHER PRACTICE ANOTHER Find the center, vertices, foci, and eccentricity of the ellipse. $4x^2 + y^2 = 64$ center (x, y) = vertices (x, y) = ) (smaller y-value) (x, y) = (larger y-value)