00:01
So to solve for this, let's calculate first the amount of oxygen gas required for the production of sulfur dioxide.
00:15
So i'm going to write here for first reaction.
00:19
First reaction.
00:23
The amount of oxygen gas, number of moles of oxygen gas, if we have 6 .30, 2 grams of sulfur, convert this to moles, divide the atomic mass of sulfur, 32 .07 grams.
00:38
We have moles.
00:39
And as you can see, in the balance equation, one mole of sulfur will react with one mole of oxygen gas.
00:48
So that means we have 0 .196 this is mole of oxygen gas.
00:54
Now, let's calculate the amount of...
00:58
For the second reaction, we need to calculate first the amount of...
01:03
Sulfur dioxide produced.
01:05
So number of moles of so2, if we have 6 .30 grams of sulfur, convert it to moles 32 .07 grams per mole.
01:17
One mole of sulfur will produce one mole of so2.
01:24
So that means we'll get your point 196 this is, mole of so2.
01:29
And for the second reaction, this reaction, the number of moles of oxygen, gas required for the amount of so2 is, you will be using the amount of so2...