00:01
Hello students, we are given by a question in which we have h2 -so -3, that is a weak acid having concentration 0 .01 molar and its dissociation constant is ka1 equal to 1 .7 into 10x power minus 2 and ka2 is 6 into 10x power minus 8.
00:19
So we have to find the correct statement regarding h -2 -s -o -3.
00:23
So firstly we have to write the dissociation that h -2 -3 dissociate into h -s -o -3.
00:31
H plus xx and hso3 minus x worse.
00:38
There will be only one dissociation.
00:41
Ka1 will be involved because ka1 is greater than ka2.
00:47
It means that the solution, solution dissociation, solution dissociation is only on the basis of, on the basis of so now h2so3 gives h plus i and hs23 minus ion.
01:17
The concentration of h2 .3 is c and there is no formation of h2s2 and h2 3 minus ion.
01:24
Then h2s2 3 is dissociated as c -mina and there is a formation of h plus that's t alpha and s23 minus equals to t alpha.
01:34
So by using this equation, we have ka that is equals to c square, alpha square and c into 1 minus alpha.
01:47
And when we calculate this, it will be c alpha square upon 1 minus alpha and 1 is higher than alpha.
01:57
So it will be, alpha will be negligible here and ka will be equals to c alpha square.
02:01
And alpha will be equal to root k -a -c...