PROBLEM 12. Determine the recations at pin in C and...

PROBLEM 12. Determine the recations at pin in C and meber BD. Members are pin connected. Solution: \frac{F_B}{DB} = 125 N, Cx = 100 N, Cy = 75 N. $M_c = 0$ $O = 200 (0.09) + DB (0.24)$ PROBLEM 13. Two rods are connected by a slider block as shown at C (only a reaction perpendicular to the block-bar). Neglecting the effect of friction, determine the moment Ma required to hold the system in equilibrium. A and B are pins. Solution: MA = 125 lb-in. $\sqrt{(15 \cos 50 + 15)^2 + (15 \sin 50)^2} = L_C$ $R_C (27.2 \ in) = 250 \ lb \times \ in$ $R_C = 9.194 \ lb$ $M_A = 15$

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sum F_{x}=0 \ O=-left(frac{240}{510} ight)255+C_{x} \ C_{x}=120N \ ext{PROBLEM 12. Determine the reactions at pin in C and member BD. Members are pin connected. Solution: } E_{B}=125N, C_{x}=100N, C_{y}=75N. DB \ M_{c}=0 \ O=200(0.09)+DB(0.24) \ ext{PROBLEM 13. Two rods are connected by a slider block as shown at C (only a reaction perpendicular to the block-bar). Neglecting the effect of friction, determine the moment Ma required to hold the system in equilibrium. A and B are pins. Solution: } MA=125lb-in. \ M_{A}=15 \ sqrt{(15cos50+15)^{2}+(15sin50)^{2}}=L_{c} \ R_{C}(27.2in)=25016sin \ R_{c}=9.194165 \ 20mm \ EF00 O=1255+C_{x} 400N C_{x}-120N 200N ext{PROBLEM 12. Determine the reactions at pin in C and member BD. Members are pin connected. Solution: } E=125N, C_{x}=100N, C_{y}=75N. DB MeFO O=2000.09+pB0.24 \ R \ 90mm \ 120mm 120mm 120 \ ext{PROBLEM 13. Two rods are connected by a slider block as shown at C (only a reaction perpendicular to the block-bar). Neglecting the effect of friction, determine the moment Ma required to hold the system in equilibrium. A and B are pins. Solution: } MA=125lb-in. \ MA=250 \ 250 lb-in. \ 15in. \ MA=15 \ 15in. \ 15cos50+15^{2}+15sin50L_{c} R27.2in=250bsm hc-9.19916s

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