Suppose 2500 J of heat are added to 3.9 mol of argon gas at a constant pressure of 120 kPa. (Assume that the argon can be treated as an ideal monatomic gas.) (a) Find the change in internal energy. (answer in: J) (b) Find the change in temperature for this gas. (answer in: K) (c) Calculate the change in volume of the gas. (m^3)
Added by Kimberly C.
Step 1
- Heat added, \( Q = 2500 \) J - Number of moles, \( n = 3.9 \) mol - Constant pressure, \( P = 120 \) kPa = \( 120 \times 10^3 \) Pa (since 1 kPa = 1000 Pa) - Argon is a monatomic ideal gas, so the degrees of freedom \( f = 3 \). Show more…
Show all steps
Close
Your feedback will help us improve your experience
Adi S and 92 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
When $20.9 \mathrm{~J}$ of thermal energy was added to a particular ideal gas, the volume of the gas changed from $50.0$ $\mathrm{cm}^{3}$ to $100 \mathrm{~cm}^{3}$ while the pressure remained constant at $1.00 \mathrm{~atm}$. (a) By how much did the internal energy of the gas change? If the quantity of gas present is $2.00 \times 10^{-3} \mathrm{~mol}$, find the molar specific heat of the gas at (b) constant pressure and (c) constant volume.
Three moles of a monatomic ideal gas are heated at a constant volume of 1.50 $\mathrm{m}^{3}$ . The amount of heat added is $5.24 \times 10^{3} \mathrm{J}$ . ( a) What is the change in the temperature of the gas? (b) Find the change in its internal energy. (c) Determine the change in pressure.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD