0:00
Hello everyone.
00:01
So in this question the three events defined are a, b, c defined as first coin is head, first is head, b as second coin is head, second is head and c as both same.
00:29
So first is head implies head, head, head or head tail.
00:35
These are the possible outcomes.
00:38
For b, that is second is head we have tail head head tail head tail head head head and for third that both are same we have tail tail tail or head head head in total point tossing of two coins implies head tail tail tail tail tail tail tail tail fine now it is given that probability first is show that probability of of a intersection b is equal to probability of a multiplied by probability of b.
01:23
We have to prove this.
01:25
So we will start with lhs.
01:28
Lhs that is probability of a intersection b which implies number in a intersection b divided by number in universal set u.
01:43
So here a intersection b means first is head as well as second is head.
01:48
So, only possible is hh, so this becomes 1 divided by total and universal set there are 4.
01:56
So probability becomes 1 divided by 4.
01:58
Now, let us come to rhs...