00:01
Hello students, let us do this question.
00:03
Here we have given data of age of teenagers when they get driving lessons for the five regions.
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The regions are north east, south, west, central and east region.
00:26
And we have to compare if the means for the five regions is same or not.
00:30
So we will use here one factor an hour.
00:33
The hypothesis to be tested here is mean for all regions is same.
00:37
So mu1 equal to mu 2 equal to mu 3 equal to mu 4 equal to mu 5, which have nothing but the population mean for these 5 regions respectively.
00:49
Alternative hypothesis here will be mu i not equal to mu j, where i comma j goes from 1 to 3, 4, 5.
01:00
I is not equal to j for at least one fair of i and j.
01:04
It means either we can have mu1 not equal to mu two or mute in mu two not equal to mu three or so on for taking various combinations of five comma j where i is not equal to j the excel steps to perform the one one factor anvice first enter data into five columns then select data go to data analysis after that no one window will open from then select and 1 factor for input range select the complete input data range alpha equal to 0 .05 if labors are selected while selecting the input then click labels equal to yes and for output range click on any blank cell and click okay then you will get the anva output the ano output the second table is nothing but the actual ano output where it contains the value of the ms degrees of freedom ss p value and f critical so from this test we can see our f test statistic value is 2 .4757...