00:01
Okay, so we're told that a professor sends an email to 200 students asking if they cheated, ever cheated on a test, 25 respond, so our sample size is going to be 25, and 4 % say they cheated, so the sample proportion is 0 .04.
00:17
There isn't actually a question included in this now, that's all the information that it tells me, it doesn't ask for any more information.
00:24
What i'm going to do is i'm going to assume it wants a 95 % confidence interval for the true proportion of people based on this sample, but if you wanted to find out something else then please re -upload the question with a different, either with a picture of what it's asking or just include a little bit of extra text with the question that you want answered so that we can help you as best we can.
00:44
So this confidence interval is going to be given by the sample proportion plus or minus the t -value with the t -distribution with 24 degrees of freedom, that's one less than the sample size, and i'll do it for the 95 % confidence interval, so we're going to be bounding the central 95%, which means that there's 2 .5 % either side, and this is the t -distribution with 24 degrees of freedom, and then times the standard error which we estimate by the sample proportion times 1 minus itself over the sample size...