Suppose a particle of ionizing radiation deposits 1.0 MeV in...

Suppose a particle of ionizing radiation deposits 1.0 MeV in the gas of a Geiger tube, all of which goes to creating ion pairs. Each ion pair requires 30.0 eV of energy. (a) The applied voltage sweeps the ions out of the gas in 1.00$\mu$ . What is the current? (b) This current is smaller than the actual current since the applied voltage in the Geiger tube accelerates the separated ions, which then create other ion pairs in subsequent collisions. What is the current if this last effect multiplies the number of ion pairs by 900?

Transcript

00:01 So for this problem, we are told that we are given that the energy deposited by the ionizing radiation is equal to 1 mega electron bolts that we can also write as 1 times 10 to the 6 electron balls.

00:24 So the energy required to create an ion pair that we call the energy.

00:33 I is equal to 30 electron balls.

00:38 So in the type taken to sweat off the ion pairs is also given and that is equal to one microsecond which is equal to 1 times 10 to the minus 6 seconds.

00:53 So the number of ion pairs is given by the following formula.

00:58 Is it the ratio between the energy deposited by the ionizing radiation and the energy required to create an ion pair.

01:13 So we will have in here that this is 1 times 10 to the 6 electron volts divided by 30 electron balls.

01:21 So from this we obtain a value of 3 .33 times 10 to the 4.

01:29 So that is the number of of par of per.

01:41 That is created.

01:43 Now from this, we are going to use the fact that since there are two charges in each pair created, the total charge can be rated as the following.

01:55 It can be rated as two times the number that we obtain times the charge of a proton that we know in magnitude is the same as the charge of an electron.

02:05 So if we substitute those values in here, we will have two times 3 .33.

02:11 Times 10 to the 4, and this times 1 .6 times 10 to the minus 19 columns...

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