suppose a random sample of 390 U.S. advertising agencies gives a 0.48 proportion of the billing volume from network television to charity. calculate the 95% confidence interval
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The sample proportion (p) is 0.48, and the sample size (n) is 390. Show more…
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Suppose that a random sample of 400 U.S. advertising agencies gives an average percentage share of billing volume from network television equal to 7.46 percent, and assume that σ equals 1.42 percent. Calculate a 95 percent confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies.
Adi S.
In an article in Marketing Science, Silk and Berndt investigate the output of advertising agencies. They describe ad agency output by finding the shares of dollar billing volume coming from various media categories such as network television, spot television, newspapers, radio, and so forth. (a) Suppose that a random sample of 406 U.S. advertising agencies gives an average percentage share of billing volume from network television equal to 7.46 percent, and assume that σ equals 1.42 percent. Calculate a 95 percent confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies. (Round your answers to 3 decimal places.) The 95 percent confidence interval is [ , ]. (b) Suppose that a random sample of 406 U.S. advertising agencies gives an average percentage share of billing volume from spot television commercials equal to 12.49 percent, and assume that σ equals 1.55 percent. Calculate a 95 percent confidence interval for the mean percentage share of billing volume from spot television commercials for the population of all U.S. advertising agencies. (Round your answers to 3 decimal places.) The 95 percent confidence interval is [ , ].
A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 581 randomly selected Americans surveyed, 406 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 95% confidence the proportion of all Americans who favor the new Green initiative is between __?__ and __?__
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