Question

Suppose 9 cards are dealt from an ordinary deck of 52 playing cards. (a) What is the probability that exactly 3 of the cards will be face cards? (b) What is the probability that at least 1 of the cards will be a king? (a) The probability that exactly 3 of the cards will be face cards is (Round to four decimal places as needed.)

          Suppose 9 cards are dealt from an ordinary deck of 52 playing cards.
(a) What is the probability that exactly 3 of the cards will be face cards?
(b) What is the probability that at least 1 of the cards will be a king?
(a) The probability that exactly 3 of the cards will be face cards is 
(Round to four decimal places as needed.)

Suppose 9 cards are dealt from an ordinary deck of 52 playing cards.
(a) What is the probability that exactly 3 of the cards will be face cards?
(b) What is the probability that at least 1 of the cards will be a king?
(a) The probability that exactly 3 of the cards will be face cards is
(Round to four decimal places as needed.)

Added by Samuel V.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Madhur L

08/17/2023

Step 1

This can be calculated using combinations, which is denoted as C(n, k) or "n choose k". In this case, we have: C(52, 5) = 52! / (5! * (52 - 5)!) Now, we need to find the number of ways to draw exactly 3 face cards and 2 non-face cards. There are 12 face cards (3 Show more…

Show all steps

Thanks for your feedback!

Suppose 9 cards are dealt from an ordinary deck of 52 playing cards. (a) What is the probability that exactly 3 of the cards will be face cards? (b) What is the probability that at least 1 of the cards will be a king? (a) The probability that exactly 3 of the cards will be face cards is (Round to four decimal places as needed.)