Suppose host a wants to send a large file to host b the path...

Suppose Host A wants to send a large file to Host B. The path from Host A to Host B has three links, of rates R1 = 1 Mbps, R2 = 2 Mbps, and R3 = 1 Mbps. Assuming no other traffic in the network, what is the throughput for the file transfer? (10 pts) Ans: ___ Mbps Suppose the file is 2 million bytes. Assume that the link distances are very small, and the propagation delays along the links are negligible. Roughly how long will it take to transfer the file from Host A to Host B in terms of seconds? (10 pts) Ans: ___ seconds

Transcript

00:01 Hello students, as the propagation delay denotes as a d drop, the propagation delay d drop is the time it takes for the signal to propagate from the host a to host b.

00:15 So it can be expressed as d drop is equal to m by s in seconds into seconds where m is the distance in meters distance in meters meters so and s is the propagation speed propagation propagation speed in the meters in meters per second in meters per second.

01:00 So the second is as the transmission time of the packet denotes as the d trans it denotes with d trans.

01:09 So where is the is the time it taken it takes to transmit the entire packet of the size l bits over the link at the rate of r bps.

01:21 So it can be expressed as d trans d trans is equal to l by r seconds l by r seconds.

01:32 So with this as l is the size as l is the size of the packets in bits in bits.

01:43 So whereas r is the transmission rate it is the transmission rate in the bits per second.

01:54 The third is the end to end delay that is denoted as d.

01:59 So is the sum of the propagation delay and the transmission time assuming the no other delay as d is equal to d prop plus d trans plus d trans.

02:14 So as the next d part is to host a begins to transmit the packet time t is equal to zero and the last bit of the packet transmitted time t time t is equal to d trans is equal to d trans.

02:32 So as the next with it as the next with it is if the d prop is greater than the d trans then it means that the propagation delay is it is longer than the transmission time at the time t is equal to the trans.

02:50 So if the d prop d prop is greater than the d trans then that means that the propagation delay is longer than the transmission time at the time t is equal to the d trans d trans...

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