00:01
Hi, i'm david and i'm here to help you answer your question.
00:03
Now let me bring up your question here.
00:05
In the question here we are going to discuss about the portion distribution.
00:09
Let me remind you that if the x that followed by the possum when the mean equal to the lambda, and then the probability of the x equal to k, equal to e to the bar minus lambda, lambda bar of k over k factorial.
00:24
In this question here, suppose then the 400 pages of the book there are 100 printing around, so we have, it will define the x equal to the number of the error, the page, and then x will follow by the possum.
00:43
Now with the lambda, it will equal to, we know that for the 400 pages, and then we will have the 100 errors.
00:54
And now it will have only one page, and then the number of the error equals to 1 times 100, the 500 equals to 1 over 5 equals to zobon 25 errors per page.
01:11
And then we have the lambda down here equal to the z1 25...