00:01
So to solve for this, let us first calculate the moles of water.
00:07
Okay, so we have 0 .90 grams of water, okay? 0 .90 grams h2o.
00:21
And then we know that the molar mass of water is 18 .02 grams per mole of water.
00:29
Therefore, the number of balls of h2.
00:33
H2o is 0 .049 moles.
00:37
Okay.
00:38
So heat therefore, that is released during condensation, right here, q, that's the heat release during condensation.
00:49
We have 0 .0499 moles of h2o, right? and for every mole of h2o, we have the constant enthalpy of vapor of water that's 44 kilojoules okay so we have here is per mole and here we have 44 kilojoules so our answer therefore is for q that's the heat release during anensation we have 2 .20 kilojoules okay and now we are to find for the final temperature of the iron okay in degrees celsius so that means we'll use this formula we have q equivalent to the mass multiplied by the specific heat capacity and then the delta t or the change in temperature the specific heat capacity of iron will be that's right here c this is a constant so you just need to check this c is c of iron is 0 .45 joles per grams degrees celsius okay that's the specific heat capacity of iron so now let's substitute our values we have the mass the mass of the iron block is 75 75 grams let's write this slide here again q is 2 .20 joles and then mass of the iron plop is 75 grams.
02:48
Specific heat capacity is 0 .45 joules per grams degrees celsius.
02:57
And then we have delta t...