00:01
Hello students in the question they given that x follows the binomial distribution of n is equal to 200 p is equal to 0 .1 now we are taking the approximate probabilities we would use the normal distribution normal approximation to binomial distribution therefore, x follows the normal distribution of mu is equal to np and sigma square is equal to np into 1 minus p, which is x follows n is equal to mu is equal to 200 into 0 .1 and sigma square is equal to 200 into 0 .9.
01:10
Therefore, x follows n, mu as equal to 20 and sigma square is equal to 18.
01:18
Now we want to calculate probability of x less than or equal to 30.
01:25
Apply the continuity correction.
01:32
We have p of x less than or equal to 30 .5, which is equal to p of x minus mu by sigma less than or equal to 30 .5 divided by 20 divided by square root of 18.
01:50
We get p of z less than 2 .48.
01:54
By using the z table, we get 0 .9933.
01:59
Then for b, we want to calculate p of 15 less than x less than 25.
02:11
By using the continuity correction, 14 .5 less than x less than x...