Suppose that 11% of people are left handed. If 8 people are selected at random, what is the probability of that exactly are 2 of them are left handed?
Added by Christopher G.
Step 1
The probability of a left-handed person is 0.11, and the probability of a right-handed person is 0.89 (since 1 - 0.11 = 0.89). The probability of a single combination is (0.11)^2 * (0.89)^6. Now, we need to find the number of possible combinations of 2 Show more…
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