Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the other team contains 25 people. Betty, Bo, and Bobby are friends and want to be on the same team. What is the probability that the three friends will be on the same team?
Added by Manuel S.
Step 1
- The number of ways the three friends can be on the same team in the first team is given by 10C3 (choosing 3 out of 10) and in the second team is given by 25C3 (choosing 3 out of 25). Show more…
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