Question

Suppose that 60% of a particular electronic part last over 3 years, while 70% last less than 6 years. Assuming a normal distribution, what are the mean and standard deviation with regard to length of life of these parts? A. μ = 3.677, σ = 3.561 B. μ = 3.977, σ = 3.861 C. μ = 4.177, σ = 3.561 D. μ = 4.377, σ = 3.261 E. The mean and standard deviation cannot be computed from the information given.

Name: suppose that 60 of a particular electronic part last over 3 years while 70 last less than 6 years assuming a normal distribution what are the mean and standard deviation with regard to length of life
Uploaded: 2022-08-08T17:54:02-08:00
Duration: 2 min 8 s
Channel: Jason Huang
Description: suppose that 60 of a particular electronic part last over 3 years while 70 last less than 6 years assuming a normal distribution what are the mean and standard deviation with regard to length of life

          Suppose that 60% of a particular electronic part last over 3 years, while 70% last less than 6 years. Assuming a normal distribution, what are the mean and standard deviation with regard to length of life of these parts?

A. μ = 3.677, σ = 3.561
B. μ = 3.977, σ = 3.861
C. μ = 4.177, σ = 3.561
D. μ = 4.377, σ = 3.261
E. The mean and standard deviation cannot be computed from the information given.

Added by Harizz K.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Jason Huang

08/08/2022

Step 1

We are given that 60% of the electronic parts last over 3 years, and 70% last less than 6 years. We need to find the mean (μ) and standard deviation (σ) of the normal distribution that describes the lifespan of these parts. Show more…

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Suppose that 60% of a particular electronic part last over 3 years, while 70% last less than 6 years. Assuming a normal distribution, what are the mean and standard deviation with regard to length of life of these parts? A. μ = 3.677, σ = 3.561 B. μ = 3.977, σ = 3.861 C. μ = 4.177, σ = 3.561 D. μ = 4.377, σ = 3.261 E. The mean and standard deviation cannot be computed from the information given.