This can be done using the multinomial coefficient:
$$\binom{52}{4,4,4,4,4,4,4,4,4,4,4,4,4} = \frac{52!}{(4!)^{13}}$$
Now, let's find the number of ways to distribute the 52 cards such that no hand has more than one ace. There are 4 aces in the deck, and we need
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