Suppose that \( G(x)=\log _{2}(2 x-2)-3 \). (a) What is the domain of G? (b) What is \( \mathrm{G}(9) \) ? What point is on the graph of \( \mathrm{G} \) ? (c) If \( G(x)=-1 \), what is \( x \) ? What point is on the graph of \( G \) ? (d) What is the zero of \( \mathrm{G} \) ?
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Therefore, we set up the inequality: \[2x - 2 > 0\] Solving for \(x\), we get: \[2x > 2\] \[x > 1\] Thus, the domain of \(G\) is \(x > 1\), or in interval notation, \((1, \infty)\). Show more…
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