Suppose that problems A and B are two different solvable decision problems, and that A is polynomially reducible to B, i.e., A ≤P B. If A is NP-complete, does this mean B must also be NP-complete? Explain and justify why or why not.
Added by Benjamin C.
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A decision problem is NP-complete if it is in the class NP and every problem in NP is polynomially reducible to it. In other words, it is one of the hardest problems in NP. Now, if A is NP-complete and A is polynomially reducible to B, i.e., A ≤P B, then it means Show more…
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