00:01
This problem says to suppose that r and s are points on the number line.
00:04
If rs, the length from r2s is 11, and s lies at 9, where could r be located? and if there's more than one location, separate them with commas.
00:14
And we are going to have more than one location here, because if we assume that we have s as our last point from our line for r to s, if this is located at 9 and we know that the entire length from r to s is 11, if we take 9 and subtract 11, that's the time.
00:30
Going to give us the point that r would need to be at if r was in front of us.
00:34
If we take 9 and add 11, that's going to tell us the position of r if r was past s.
00:41
So when we look at 9 minus 11, so under the assumption that r comes before s on the number line, 9 minus 11 gives us negative 2.
00:50
That means that r could be located at negative 2 for one location, but it could also be located at 9 plus 11, which is 20...