Suppose that resting pulse rates among healthy adults are normally distributed with a mean of 73 beats per minute and a standard deviation of 20 beats per minute. Find the percentage of healthy adults who have resting pulse rates that are more than 99 beats per minute. For your intermediate computations, use four or more decimal places. Give your final answer to two decimal places (for example 98.23%).
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Step 1
Given: Population mean, μ = 73 Population standard deviation, σ = 20 Resting pulse rate, x = 99 Calculate the z-score: \[ z = \frac{x - \mu}{\sigma} = \frac{99 - 73}{20} = \frac{26}{20} = 1.3 \] Show more…
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