00:01
To calculate the final temperature of the mixture, we need to figure out which reactant is limiting.
00:07
Our chemical reaction has a stoichiometry of one -to -one.
00:11
So if we start with our 150 milliliters of hcl and divide it by 1 ,000, we'll get liters of hcl.
00:18
We can then use the molarity of hcl to calculate the moles of hcl, and then recognize 1 -mole hcl produces 1 mole.
00:27
We'll choose one of these products.
00:28
1 -mole sodium chloride.
00:31
So if all the hcl reacts would get 0 .075 moles of nacl.
00:37
We'll do a similar calculation with sodium hydroxide, 50 milliliter sodium hydroxide divided by 1 ,000 to get it in liters, and then multiply by its molarity of 1 molar to get mole sodium hydroxide.
00:51
And then we'll use the stoichiometry 1 to 1 to get mole sodium chloride.
00:56
So if all the sodium hydroxide reacts, we'll get 0 .000 to 1 -1 to get 0 .000.
00:59
0 .05 moles sodium chloride...