2 \text{ V/m})x$, we can find the derivative with respect to $x$:
$$\frac{dV}{dx} = \frac{d}{dx}((2.2 \text{ V/m})x) = 2.2 \text{ V/m}$$
Therefore, the electric field is:
$$E = -2.2 \text{ V/m}$$
The magnitude of the electric field is $|E| = 2.2 \text{ V/m}$. This
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