Question

Suppose that the function g is defined, for all real numbers, as follows. \begin{equation} g(x) = \begin{cases} \frac{1}{2}x - 1 & \text{if } x \neq -2 \\ 3 & \text{if } x = -2 \end{cases} \end{equation} Find $g(-5)$, $g(-2)$, and $g(4)$.

          Suppose that the function g is defined, for all real numbers, as follows.
\begin{equation*}
g(x) = \begin{cases}
\frac{1}{2}x - 1 & \text{if } x \neq -2 \\
3 & \text{if } x = -2
\end{cases}
\end{equation*}
Find $g(-5)$, $g(-2)$, and $g(4)$.

Suppose that the function g is defined, for all real numbers, as follows.

g(x) = (1)/(2)x - 1 if x ≠ -2

3 if x = -2

Find g(-5), g(-2), and g(4).

Added by Kathryn T.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Tim Thornhill

07/28/2022

Step 1

Since -5 is not equal to -2, we can use the function g(x) = (1/2)x - 1. g(-5) = (1/2)(-5) - 1 g(-5) = -5/2 - 1 g(-5) = -7/2 Show more…

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Suppose that the function g is defined, for all real numbers, as follows. g(x)={((1)/(2)x-1 if x!=-2),(3 if x=-2):} Find g(-5),g(-2), and g(4) Suppose that the function g is defined, for all real numbers, as follows g(x) 3 ifx=-2 Find g-5),g-2),and g4).