00:01
Hi, i'm david and i'm here to help you answer your question.
00:03
Now let me bring up your question here.
00:05
In the question here, we are going to discuss about the possum process.
00:09
Now if we have the n will follow by the possum process with the rate equal to the lambda and then the inter -arrival time.
00:28
T it will follow by exponential with the rate also equal to the lambda and then the density of the t will equal to lambda e to the bow minus lambda x for the x squared equal to the 0.
00:42
Now in this question here we have the lock on to the computer next word has the possum process with the average three count per minute.
00:52
So n will follow by the possum with the lambda equal to the three per minute.
00:59
And therefore we will have the interrable time.
01:02
T it will be followed by exponential with the lambda also equal to the three minute and then we will have the density of the t it will equal to the three e to the power minus lamb equal minus three t sorry this one should be the t not the x here and then for the t it could be greater than the zero and in the first question a, asking that you find the mean time between the account.
01:53
So it means that one to find the e on the t.
01:56
And e on the t for the exponential, it will equal to one over the lambda, it will equal to one over three...
