Suppose that the variable X is normally distributed with mean of 150 and standard deviation of 25. Find the probability that X is more than 167. (a) 0.9830 (b) 0.7517 (c) 0.2483 (d) 0.6632 (e) None of the aobve
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The z-score is calculated as: z = (X - μ) / σ where X is the value we're interested in, μ is the mean, and σ is the standard deviation. Plugging in the values, we get: z = (167 - 150) / 25 = 17 / 25 = 0.68 Now, we need to find the probability that X is more Show more…
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