00:01
All right, so we have a restaurant that needs a staff of three waiters and two chefs, x waiters, y, chefs.
00:10
We have a joint distribution here.
00:13
And the first question is we have to find the value of k.
00:16
And the k is going to be right here in the zero zero cell.
00:20
And the way we do this is we know that all these probabilities should sum to one.
00:24
But if you sum everything but this value, it's going to be 0 .94.
00:31
And we need it to be 1 % or 1 or 100 % i mean.
00:36
So we need k to be 0 .06 to make this a probability distribution.
00:42
What's the probability that at least one waiter and at least one chef show up on any given day? so let's get that.
00:49
We figured out k.
00:50
So at least one waiter that's from here and above, all these values.
00:57
That's all this.
00:58
These, i'm going to actually go like this.
01:03
All this stuff here.
01:04
These are at least one waiter but we also want at least one chef so that's and then we want the overlap so it's these these six right here so you add these up 0 .64 point six four point or 0 .04 0 .05 0 .06 0 .06 .04 and we end up with 0 .87 right what's the probability that more chefs show up than waiters.
01:43
So let's go back to this.
01:45
More chefs than waiters.
01:47
Let's see.
01:47
Where is that the case? zero, no, that's not it.
01:50
One, zero.
01:51
Oh, that would be the case.
01:52
This is going to be one to use.
01:57
Two is greater than zero, so yeah.
01:59
So if you have zero waiters, as long as you have one or two chefs, that qualifies.
02:03
Let's see, one waiter.
02:06
You need at least the two chefs to be more than the waiter.
02:10
So it's these three cells.
02:11
So you add these up.
02:12
0 .02 .1.
02:13
0 .03 .06.
02:15
That's the probability that more chefs show up than waiters.
02:21
What's the probability that more than one, that more than three total staff, wares and chefs will show up in any given day? so this we want where the sums of x and y are three, or three or more.
02:37
So let's see, one and two, one waiter and two chefs would work, but you can't combine one with zero or one to make three, so we don't do that.
02:47
But two could be combined with one or two chefs to be greater than three.
02:52
That works.
02:53
And then three, because we just want three total staff, so we add these six values.
03:01
Or something else we could do.
03:02
Well, yeah, we could do that.
03:03
Or we could add these up and subtract it from one from one.
03:09
But either way, you get the same amount.
03:14
So 0 .65 plus 0 .04, more than three total.
03:25
So, because that's five.
03:28
That's what i have here.
03:29
So this is total of five.
03:30
This is four.
03:31
This is three and three and three.
03:33
So it's these little triangle cells, which are those ones there.
03:39
So we add these up.
03:41
0 .65, 0 .04, 0 .02, 0 .05, 0 .06, and 0 .03.
03:53
Wait.
03:54
So i'm sorry.
03:54
I read that more than three.
03:59
So strictly more than three.
03:59
So not three or more.
04:00
So it's just these ones, four, four, and five.
04:04
So it's not those.
04:06
Because i was going back, i was like, wait a second, that's, it's not right.
04:08
It's these, these ones add together.
04:10
0 .05, 0 .04, 0 .65.
04:13
There you go.
04:13
So it's 0 .74.
04:14
What's the expected total number of staff? waiters and chefs that will show up in any given day.
04:20
So the expected value, it's going to be the expected value of x plus y.
04:32
And that's equal to the sum of all the x plus y values multiplied by their.
04:40
Respective probabilities.
04:44
We add those up...