Question

Suppose that the weight, $X$, in pounds, of a 40-year-old man is a normal random variable with mean 147 and standard deviation 16. Determine $P(120 \le X \le 153)$. Round your answer to four decimal places. Provide your answer below $P(120 \le X \le 153) = $

Name: suppose that the weight x in pounds of a 40 year old man is a normal random variable with mean 147 and standard deviation 16 determine p120 le x le 153 round your answer to four decimal plac 70393
Uploaded: 2024-03-15T23:08:01-08:00
Duration: 1 min 44 s
Channel: Pritesh Ranjan
Description: suppose that the weight x in pounds of a 40 year old man is a normal random variable with mean 147 and standard deviation 16 determine p120 le x le 153 round your answer to four decimal plac 70393

          Suppose that the weight, $X$, in pounds, of a 40-year-old man is a normal random variable with mean 147 and standard deviation 16.
Determine $P(120 \le X \le 153)$. Round your answer to four decimal places.
Provide your answer below
$P(120 \le X \le 153) = $

suppose that the weight x in pounds of a 40 year old man is a normal random variable with mean 147 and standard deviation 16 determine p120 le x le 153 round your answer to four decimal plac 70393

Added by Noelia E.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Pritesh Ranjan

03/15/2024

Step 1

We need to find the probability $P(120 \le X \le 153)$. To do this, we will convert the $X$ values to $Z$-scores using the formula: $Z = (X - \mu) / \sigma$ For $X_1 = 120$: $Z_1 = (120 - 147) / 16 = -27 / 16 = -1.6875$ For $X_2 = 153$: $Z_2 = (153 - 147) / 16 Show more…

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Suppose that the weight, $X$, in pounds, of a 40-year-old man is a normal random variable with mean 147 and standard deviation 16. Determine $P(120 \le X \le 153)$. Round your answer to four decimal places. Provide your answer below $P(120 \le X \le 153) = $