Question

Suppose that we determined from a sample of 42 customers that the average amount spent on a smoothie at Jamba Juice is $6.89. From historical data, it is known that the population standard deviation is $1.06. It is assumed that the distribution for the amount spent on a smoothie at Jamba Juice is approximately normal. 1.) Construct an 88% confidence interval for the population mean. A.) $6.64 and $7.14 B.) $6.62 and $7.16 C.) $6.56 and $7.22 D.) $6.57 and $7.21 2.) Suppose that we would like to construct an 88% confidence interval within a margin of error E = $0.25. How many customers should be surveyed? A.) 43 B.) 44 C.) 7 D.) 49

          Suppose that we determined from a sample of 42 customers that the average amount spent on a smoothie at Jamba Juice is $6.89. From historical data, it is known that the population standard deviation is $1.06. It is assumed that the distribution for the amount spent on a smoothie at Jamba Juice is approximately normal.

1.) Construct an 88% confidence interval for the population mean.
A.) $6.64 and $7.14
B.) $6.62 and $7.16
C.) $6.56 and $7.22
D.) $6.57 and $7.21

2.) Suppose that we would like to construct an 88% confidence interval within a margin of error E = $0.25. How many customers should be surveyed?
A.) 43
B.) 44
C.) 7
D.) 49

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Added by Calvin R.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Clarissa Barr

07/02/2023

Step 1

) To construct an 88% confidence interval for the population mean, we need to use the formula: CI = x̄ ± zα/2 * σ/√n where x̄ is the sample mean, σ is the population standard deviation, n is the sample size, zα/2 is the z-score corresponding to the desired Show more…

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Suppose that we determined from a sample of 42 customers that the average amount spent on a smoothie at Jamba Juice is $6.89. From historical data, it is known that the population standard deviation is $1.06. It is assumed that the distribution for the amount spent on a smoothie at Jamba Juice is approximately normal. 1.) Construct an 88% confidence interval for the population mean. A.) $6.64 and $7.14 B.) $6.62 and $7.16 C.) $6.56 and $7.22 D.) $6.57 and $7.21 2.) Suppose that we would like to construct an 88% confidence interval within a margin of error E = $0.25. How many customers should be surveyed? A.) 43 B.) 44 C.) 7 D.) 49

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