Suppose that X is normally distributed with mean 125 and standard deviation 19. A) What is the probability that X is greater than 161.29? B) What value of X does only the top 20% exceed?
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29 using the z-score formula: \[ Z = \frac{X - \mu}{\sigma} = \frac{161.29 - 125}{19} = \frac{36.29}{19} = 1.91 \] Show more…
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