Question

Suppose that you were to solve this problem by the following method: \frac{4x + 8}{4} = \frac{60}{4} x + 8 = 15 -8 -8 x = 7. Part B The answer here, x = 7, is not in the interval that you selected in the previous part. What is wrong with the work shown above? To correct the work shown before Part B in the last step, 15 should be subtracted from each side. in the last step, the value 8 should be added rather than subtracted. in the first step, both terms on the left should be divided by 4. in the first step, 60/4 should yield 16, not 15.

          Suppose that you were to solve this problem by the following method:
\frac{4x + 8}{4} = \frac{60}{4}
x + 8 = 15
-8	-8
x = 7.
Part B
The answer here, x = 7, is not in the interval that you selected in the previous part. What is wrong with the work shown above?
To correct the work shown before Part B
in the last step, 15 should be subtracted from each side.
in the last step, the value 8 should be added rather than subtracted.
in the first step, both terms on the left should be divided by 4.
in the first step, 60/4 should yield 16, not 15.

Suppose that you were to solve this problem by the following method:
(4x + 8)/(4) = (60)/(4)
x + 8 = 15
-8 -8
x = 7.
Part B
The answer here, x = 7, is not in the interval that you selected in the previous part. What is wrong with the work shown above?
To correct the work shown before Part B
in the last step, 15 should be subtracted from each side.
in the last step, the value 8 should be added rather than subtracted.
in the first step, both terms on the left should be divided by 4.
in the first step, 60/4 should yield 16, not 15.

Added by Hector B.

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