00:01
Hello students, as per the given question, let us first calculate the expected frequencies.
00:08
So, expected frequencies under 5 is equals to 0 .058 into 491 which is equals to 28 .478, is approximated to 28 in general.
00:27
So, the expected of 5 to 14 which gives 0 .1 into 491 which is equals to 49 .1 and value for expected value for 15 to 64 is 0 .738 into 491 which gives the value as 362 .658 and the expected value for 65 to older is 0 .104 into 491.
01:16
So, which gives 51 .064 which is approximately equals to 51 and this value is approximately equals to 362.
01:28
So, we need to find the hypothesis where for the null hypothesis, we say that the distributions are same and for the alternative hypothesis, we say that the distributions are not same.
01:43
So, calculating the test statistics which is chi square is equals to observed value minus expected value by expected value.
01:53
So, let us substitute the values in the formula which gives, we need to calculate for all the values in this way and this value is again divided by expected value.
02:09
So, likewise we need to calculate for all the 4 values where chi square gives 9 .566 as the test statistics.
02:19
So, in the next step, let us calculate the degrees of freedom and find for the respective critical value...