Suppose the binomial expansion of 3x4yn includes the term...

Transcript

00:01 This term tells us a lot of information about what's going on with our expansion.

00:05 So we know that it's the 3x plus 4y to the nth power.

00:10 These two things together are going to tell you what that nth power is, because one of them is going to have the n -mines r, and the other one's going to actually be r.

00:19 So these two together tell us what the n is going to be, in this case is going to be 7.

00:24 So what we're looking at here is the 3x plus 4y to the 7th power.

00:31 So we're looking at the terms that have the x of the 3rd and y to the 6th in them.

00:37 So when we put them together, that will be the result.

00:43 But based upon the given information here, this one is not possible because if we add those up 3 and 6, we're not going to get 7.

00:51 So let's say it's said equal to 4, so i can show you the process that we would take.

00:55 So if we're doing that, then the beginning of it is going to be seven, choosing four, because the second one is r.

01:03 And then we would have the first term, 3x, raised to the fourth, the third power, because it's 7 minus 4.

01:11 And then we would have 4 y, and that would raise up to the fourth power.

01:17 So that's one's going to match there.

01:19 Same thing here.

01:20 So we're going to have 7c, and then in this case looks like we're using 5.

01:24 So this one will be 3x to the second power, and then 4y to the fifth power.

01:31 So what we're going to do is just simplify that, starting off with this 7 -2s -4.

01:36 So up to you how you want to do it...

Question

Suppose the binomial expansion of (3x+4y)^n includes the term 181440x^4y^3. The x^3y^6 term in the expansion will be The x^2y^5 term in the expansion will be

Question

Suppose the binomial expansion of (3x+4y)^n includes the term 181440x^4y^3. The x^3y^6 term in the expansion will be The x^2y^5 term in the expansion will be

Please give Ace some feedback