Suppose the investigators had made a rough guess of 330 for the value of s before collecting data. What sample size would be necessary to obtain an interval width of 45 ml for a confidence level of 95%? (Round your answer up to the nearest whole number.) children
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The formula is: \[ n = \left( \frac{Z \cdot s}{E} \right)^2 \] Where: - \( n \) = required sample size - \( Z \) = Z-value corresponding to the desired confidence level - \( s \) = estimated standard deviation - \( E \) = margin of error (half the width of the Show more…
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Suppose the investigators had made a rough guess of 320 for the value of s before collecting data. What sample size would be necessary to obtain an interval width of 45 ml for a confidence level of 95%? (Round your answer up to the nearest whole number.) children
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