00:01
Hi, i'm david and i'm here to help you answering your question.
00:03
Now let me bring up your question here.
00:06
In the question here, we are going to discuss about the normal distribution.
00:11
Let me remind you that if we have the x that follows by the normal, when the mean and the standard deviation, and if we tell the x minus the mean of the standard deviation, we have to understand the normal.
00:23
But if the sample mean x bar, we minus the mean over the standard deviation, we need to divide extra, square to the end in order to obtain the standard normal.
00:35
In the question here, we're given the length of the pregnancy x will follow by the normal, when the mean equal to the 180, standard division equal to the 16.
00:47
Now in the question a, we need to find the probability that a random selected x will be less than the 175.
00:58
Now to find this probability, i need to convert the x into the z.
01:01
To do it and i need to use this formula therefore we'll get equal to the 175 will minus the mean over the standard division 16 and if we compute we will have the probability the z smaller than the 5 minus 5 the 116 equal to the manager bond 3125 and i use a calculator to compute this probability so we have smaller than and the minus 0 .3125 and we get equal to the 0 .3 737.
01:45
Now for the question p, want to find the probability, suppose now symbol n equal to the 20 and want to find the probability and describe the sampling description of the sample mean.
02:00
So the sampling on the x bar, it will follow by normal as well with the mean of the x -par equal to the mean of the population equal to 180 standard division x -par equal to sigma a score to the n equal to the 16 divided square into the 20 and then we get equal to even with square root of the 20 equal to 3 .577 8 and then for the next question here i'm going to the probability for the question c the probability that the sample mean x -par will be less than the 175 again i need to confirm the x -brain to the z but now i'm going to do the formula for the x -par so with 10 the 175 i will minus the mean divided by the standard division 3 1 5778 and if we compute we have the minus 5 depends equal to the minus 1 .3 1 .375 and then we'll have this one will be minus 1 .39975 and then we get equal to this one will be x z smaller than the minus 1 .39975 and we equal to the 0 .08 1 .1.
03:46
And for the question d, want to find the probability that the symbol now n equal to the 59 has the mean will be less than this.
03:56
So now n here equal to the 59.
03:59
So xbars smaller than the 175 again...