Suppose the population variance is 25, an SRS of n=100 is obtained, and the confidence level is chosen to be 98%. The margin of error for estimating a mean is given by: O 5.825 O 3.2 O 1.165. O 0.1165.
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For a 98% confidence level, the alpha level $\alpha = 1 - 0.98 = 0.02$. We need to find the z-score such that the area to its left is $1 - \alpha/2 = 1 - 0.02/2 = 1 - 0.01 = 0.99$. Using a standard normal distribution table or calculator, the z-score for an area Show more…
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