00:01
Here time between arrivals of customer at a store closely follows an exponential distribution.
00:06
So, x b exponential lambda where mean is equal to 1 divided by lambda and mean we are given in the question as 6 .34 minute.
00:30
So 1 by lambda is equal to 6 .34 and lambda is equal to 1 .34 and lambda is equal to 1 divided by 6.
00:40
In part a we have to find out probability that arrival of the next customer is less than three minute now part a probability that x smaller than x will be equal to 1 minus exponential raised to power minus lambda x now putting values so p x smaller than 3 will be equal to 1 minus e raised to power 3 3 divided by 6 .34 as lambda we have 1 divided by 6 .34.
01:24
So calculating these values we will get 0 .370.
01:31
So this is the answer for part a.
01:33
In part b we have to calculate probability that the arrival of the next customer is more than 10 minutes.
01:41
So it will be equal to probability x greater than x will be equal to to e raised to power minus lambda x.
01:54
So probability that x is greater than 10 will be equal to e raise to power minus 10 divided by 6 .34.
02:10
So calculating these values we will get 0 .2065...