Suppose there are eight points on a circle, equally spaced. a) How many triangles are there that have their vertices among these points? b)How many of these are right triangles?
Added by Jose Manuel F.
Step 1
This can be done in 8C3 ways. The formula for combination is nCr = n! / r!(n-r)!. So, 8C3 = 8! / 3!(8-3)! = 56. Show more…
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