Given:
\( Q = \pm 13 \mu C = \pm 13 \times 10^{-6} C \)
\( \epsilon_0 = 8.854 \times 10^{-12} \, C^2/N \cdot m^2 \)
\( A = 5m \times 5m = 25m^2 \)
Plugging in the values:
\( F = \frac{(13 \times 10^{-6})^2}{2 \times 8.854 \times 10^{-12} \times 25} \)
\( F =
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