00:01
So for this problem, when we're discussing the distribution of the x -bars, the sample means, they would be following a normal distribution where the mean value of the means is equal to that of the population, so that would be 80.
00:13
But we'll have that the standard deviation of the sample means will be equal to that of the population, divided by the square root of the sample size.
00:22
So our standard deviation here of x -bar is 20 over square root of 64, which gives us a result of 2 .5.
00:30
As the standard deviation for the corresponding distribution.
00:34
Then for part b, finding the z value corresponding to x bar equals 75, so z is equal to the given value minus the mean value of the x bars.
00:48
I will note here that in the upload of the problem, there are references to x, but we're dealing with a sample of size 64.
00:58
So contextually, i'm assuming that that is supposed to be x bar, and that this was simply miscopied.
01:04
That being said, for part b, the z score corresponding to a sample mean of 75, we do, well, x bar minus mu x bar, divided by sigma x bar.
01:16
So, in this case, well, we know that the sample mean is 75...