0:00
Hello.
00:02
So you have a mean here of 10, summed division of 2.
00:08
This is a normal distribution.
00:11
Let's look at a, where we have a probability of its beta diameter of 4.
00:18
So because we have a normal distribution, we're going to be using this formula, which is just going to be 4 minus 10.
00:27
2.
00:31
This is just z.
00:33
What is this? this is negative 6 divided by 2.
00:38
Negative 3, it is the same as 1 minus the probability of z, maybe a negative 3.
00:46
So we use the z table and check for the probability when z is negative 3.
00:54
So for negative 3, the probability is 0 .0 -135, if it's 0 .135, so the required probability.
01:10
So we're going to be 0 .9 -865.
01:22
2 .5.
01:37
This is the same formula.
01:44
6 .5 minus mean 10.
01:48
10 division 2.
01:52
Z less than equal to 3 .5 divided by 2.
02:01
That's negative.
02:12
We use the z table again.
02:14
0 .z is minus 1 .75.
02:17
What is the problem? let's see.
02:22
That is going to be 0 .04.
02:26
0 .06.
02:27
Yeah, 0 .04, 06.
02:36
Let's look at c, 7, 6.
02:49
Let's go to x, let down 1 equal 2.
02:56
So same formula, right? we have 10 .76 minus 10, we have standard division 2.
03:04
Let down x minus 2 and then on the right, we have 14.
03:10
1 9, 10 also over 2.
03:19
Let me see this is, we're running by 2...