Suppose you are given \( \triangle A B C \) where \( m \angle A=41^{\circ}, m \angle C=67^{\circ} \), and \( m \overline{A C}=8 \) inches. How many inches is side BC to the nearest tenth of an inch? Round only your final answer.
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Given that the sum of the angles in any triangle is 180 degrees, we can find the measure of angle B by subtracting the sum of the measures of angles A and C from 180 degrees. \[ m \angle B = 180^{\circ} - (m \angle A + m \angle C) \] \[ m \angle B = 180^{\circ} - Show more…
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