Suppose you are testing the hypotheses H0 : p = 0.23 vs. p ? 0.23 with significance level ? = 0.05. A sample size of 287 results in a sample proportion of 0.29. As you know, one way to address two-sided tests is to create confidence intervals. Construct the appropriate confidence interval for p that could be used to address the test and report the lower limit of the confidence interval. Note: 1- Only round your final answer to 2 decimal places. Enter your final answer with 2 decimal places. 2- Your final answer should be expressed as a decimal and not a percentage.
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96), p is the sample proportion (0.29), and n is the sample size (287). ME = 1.96 * sqrt(0.29 * (1-0.29) / 287) ME = 0.0525 Show more…
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